2x^2+36x+108=0

Solution for 2x^2+36x+108=0 equation:

2x^2+36x+108=0

a = 2; b = 36; c = +108;
Δ = b2-4ac
Δ = 362-4·2·108
Δ = 432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{432}=\sqrt{144*3}=\sqrt{144}*\sqrt{3}=12\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-12\sqrt{3}}{2*2}=\frac{-36-12\sqrt{3}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+12\sqrt{3}}{2*2}=\frac{-36+12\sqrt{3}}{4}
$